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Test
too bad...
When the [H
+
] is given, the other values are readily determined by the series of steps shown below.
[OH
-
]=10
-14
/[H
+
]
=>
10
-14
/7.41e-2=1.35e-13
pH=-log[H
+
]
=>
-log7.41e-2=1.13
pOH=-log[OH
-
]
=>
-log1.35e-13=12.87
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